let us c solutions pdf- Hello everyone, in this article we will discuss about the computer language programming book which are solution by yashwant kanetkar pdf.
The updated edition of the book has been thoroughly revamped to serve the students, teacher and software professionals around the world. As we all know technical C language knowledge plays a very vital role to understand the coding and programming language.
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let us c by yashwant kanetkar pdf
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Let Us C Solutions book. Read 46 reviews from the world's largest community for readers. This article is from solution of Let Us C by Yashwant Kanetkar. I also posted many another articles regarding solutions of Let Us C. If you have any problem regarding solution then give comment, I will surely reply your question. According to a study, the approximate level of intelligence of a person can be calculated using the following.
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About let us c pdf book
Book Name –Solution let us c by yashwant kanetkar pdf
Author Name- — Yashwant kanetkar
Format- PDF
Size- mb
Pages- 433(English)
Language- English
Publication- BPB Publication
Let us c solutions pdf Contents
- Introduction
- Before we begin
- Getting Started
- C Instructions
- Decision control instructions
- More complex decision making
- Loop control instructions
- More complex repetitions
- Case control instructions
- Functions
- Pointers
- Recursion
- Data types revisited
- The C Preprocessor
- Arrays
- Multidimensional Arrays
- Strings
- Handling multiple strings
- Structures
- Console input/output
- File input/output
- More issue in input/output
- Operations on bits
- Miscellaneous Features
- C under linux
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This let us c by yashwant kanetkar pdf is important to understand C language, especially to learn C programming language. So all the aspirants who want to learn C programming can easily download pdf from the above link.
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[E] Attempt the following:
(a)Write a program to print all prime numbers from 1 to 300. (Hint: Use nested loops, break and continue)
click here for Answer!!!
Answer:
void main()
{
int no,i,rem,j,flag=0;
for(no=2;no<=300;no++) { flag=0; j=no/2; for(i=j;i>=2;i--)
{
rem=no%i;
if(rem0)
{
flag=1;
break;
}
}
if(flag!=1)
printf('%dn',no);
}
}
(b)Write a program to fill the entire screen with a smiling face. The smiling face has an ASCII value 1.
click here for Answer!!!
Answer:
void main()
{
int smiling=1,i;
for(i=1;i<=2000;i++)
{
printf('%c',smiling); }
}
(c)Write a program to add first seven terms of the following series using a for loop: 1/1! + 2/2! + 3/3! + .........
click here for Answer!!!
Answer:
void main()
{
int factorial,fact,i;
float sum=0.0;
i=0;
while(i<=7) { fact=i;//for finding factorial see note: 1. factorial=1; while(fact>=1)
{
factorial=factorial*fact;
fact--;
}
sum=sum+(float)i/factorial;//int/int gives integer value so
// we converted into float value.
i++;
}
printf('sum upto 7th term is %f',sum);
}
(d)Write a program to generate all combinations of 1, 2 and 3 using for loop.
click here for Answer!!!
Answer:
void main()
{
int i,j,k,l,count=0;
for(i=1;i<=4;i++)
{
for(j=1;j<=4;j++)
{
for(k=1;k<=4;k++)
{
for(l=1;l<=4;l++)
{
if(i!=j&&j!=k&&i!=k&&i!=l&&j!=l&&k!=l)
{
printf('n%d %d %d %d',i,j,k,l); count++; }
}
}
}
}
printf('ncount = %d',count);
}
(e) According to a study, the approximate level of intelligence of a person can be calculated using the following formula: i = 2 + ( y + 0.5 x ) Write a program, which will produce a table of values of i, y and x, where y varies from 1 to 6, and, for each value of y, x varies from 5.5 to 12.5 in steps of 0.5.
Chapter 2 Let Us C Solutions
click here for Answer!!!
Answer:
void main()
{
int y;
float i,x;
for(y=1;y<=6;y++)
{
for(x=5.5;x<=12.5;)//x varies from5.5 to 12.5 so
{
i=2+(y+0.5*x); //formula
printf('i=%f y=%d x=%fn',i,y,x);//displaying
x=x+0.5; //x increase in step of 0.5 by question
}
}
}
(f)Write a program to produce the following output:
Let Us C Solutions 5th Edition Chapter 2
click here for Answer!!!Answer:
void main()
{
int i,j,k,count1,count2=0;
for(i=104;i>=97;i--)
{
for(j=97;j<=104;j++)
{
if(i>=j)
printf('%c ',j);
}
for(count1=0;count1
if(i103)
count2=count2+1;
else
count2=count2+2;
printf('n'); //new line for each i.
}
}
[7]int i=10;
(g)Write a program to fill the entire screen with diamond and heart alternatively. The ASCII value for heart is 3 and that of diamond is 4.
click here for Answer!!!
Answer:
void main()
{
int i;
for(i=0;i<=600;i++)
{
printf(' %c %c',3,4);
}
}
(h)Write a program to print the multiplication table of the number entered by the user. The table should get displayed in the following form. 29 * 1 = 29 29 * 2 =58 ....
click here for Answer!!!
Answer:
void main()
{
int no,i,multiply;
printf('enter number for multiplication table:');
scanf('%d',&no);
for(i=1;i<=9;i++)//we can make upto any number.
{
multiply=no*i;
printf('n%d * %d = %d',no,i,multiply);
}
}
(i) Write a program to produce the following output:
click here for Answer!!!
Answer:
void main()
{
int i,j,k,cnt=1,icpy,icpy1,space,count=10;
for(i=1;i<=5;i++) { for(space=count;space>=1;space--)
/*this is for managing spaces. atfirst there will be 10 spaces
which gradually decreases by 1.In output 2 is at 1
space left of 1.so, we decrease by 1*/
{
printf(' ');
}
count=count-1;
icpy=i;
for(j=1;j<=i;j++)
{
printf('%d ',icpy);
icpy++;
}
printf('n');
}
}
(j)Write a program to produce the following output:
click here for Answer!!!
Answer:
void main()
{
int a,b,c,line,space,i,j,n,r,ncr,fact_r,fact_n,factn_r;
printf('please enter the number of lines of the pascal triangle: n');
scanf('%d',&line);
printf('n');
for(i=0;i<=line;i++)
{
fact_n=1;
fact_r=1;
factn_r=1;
for(space=line;space>=i;space--)
{
printf(' ');
}
for(j=0;j<=i;j++) { n=i; r=j; fact_n=1; fact_r=1; factn_r=1; if(n0) fact_n=1; else { for(a=n;a>=1;a--)
fact_n=fact_n*a;
}
//factorial of fact_r.
if(r0)
fact_r=1;
else
{
for(b=r;b>=1;b--)
fact_r=fact_r*b;
}
if((n-r)0)
factn_r=1;
else
{
for(c=(n-r);c>=1;c--)
factn_r=factn_r*c;
}
ncr=fact_n/(fact_r*factn_r);
c(n,r)
printf('%2d',ncr); //2 space for each ncr
}
printf('n'); //new line after each row.
}
}
(k)A machine is purchased which will produce earning of Rs. 1000 per year while it lasts. The machine costs Rs. 6000 and will have a salvage of Rs. 2000 when it is condemned. If 12 percent per annum can be earned on alternate investments what would be the minimum life of the machine to make it a more attractive investment compared to alternative investment?
click here for Answer!!!
Answer:
void main()
{
int year=0,inv,altn;
while(altn>inv)
{
year++;
altn=120*year; // 12%of 1000 = 120
inv=(1000*year)-4000;
}
printf('The minimum year is %d',year);
}
(l) When interest compounds q times per year at an annual rate of r % for n years, the principle p compounds to an amount a as per the following formula
a = p ( 1 + r / q ) ^ nq
Write a program to read 10 sets of p, r, n & q and calculate the corresponding as.
click here for Answer!!!
Chapter 2let Us C Solutions Collection Agency
Answer:
void main()
{
int p,r,n,q,a,i,j,product;
float amt=1;
for(i=0;i<10;i++)
{
amt=1;
printf('enter the values of p,r,n and q: '); scanf('%d%d%d%d',&p,&r,&n,&q);
product=n*q;
for(j=1;j<=product;j++)
{
amt = amt * ( 1 +(float) r / q );
}
amt= p *amt;
printf('%f',amt);
}
}
(m)The natural logarithm can be approximated by the following series.
(x-1)/x + 1/2((x-1)/2)^2 + 1/2((x-1)/2)^3 + ...
If x is input through the keyboard, write a program to calculate the sum of first seven terms of this series.
Chapter 2let Us C Solutions Corp
click here for Answer!!!
Chapter 2let Us C Solutions Inc
Answer:
void main()
{
int x,i,j;
float sum=0,power=1;
printf('enter x for sum upto 7th term: ');
scanf('%d',&x);
for(i=1;i<=6;i++)
{
power=1;
for(j=0;j<=i;j++)
{
power = power * ((x-1.0)/2.0);
}
sum = (1.0/2) * power + sum;
}
sum=sum + (float)(x-1.0)/x; printf('%f',sum);
}